## Questions d'entretien

Entretien pour Summer Internship - Quantitative Investment Strategies

-New York, NY

# Suppose that you have a fair coin. You start with \$0. You win 1\$ each time you get a head and loose \$1 each time you get tails. Calculate the probability of getting \$2 without getting below \$0 at any time.

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## Réponses aux questions d'entretien

6 réponse(s)

3

1/3

Vipin Agrawal le

5

1/3 Because if he requires 2 heads = \$2, then it means he require HH out of {HH,HT ,TH,TT} We cannot consider TT because it would turn to zero. Therefore, he has 1 chance out of 3. Hence 1/3.

Karan More le

1

Marchov chain with 2 and -1 absorbing OR geometric series 1/4^n from 1 to inf=1/3

Utilisateur anonyme le

0

p = 0.5(0.5+0.5p)

Utilisateur anonyme le

1

Each flip has a .5 possibility of being head. (.5)(.5)=.25 or 1/4

Utilisateur anonyme le

3

Draw a tree to have an idea of how to compute the probability. The flips are all independent with each other.

Utilisateur anonyme le

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