## Questions d'entretien

Entretien pour Program Manager

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# what is angle between hour hand and minute hand in clock at 4:20 ? what is biggest conflict management you have handled in your work place

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## Réponses aux questions d'entretien

11 réponse(s)

16

IF min's hand rotates for 360 deg, hr's hand rotates for 30 deg - so for 60 min - hr's hand rotates for 30 deg. For 1 min it rotates for 0.5 degree. Hence, for 20 min it rotates for 10 degrees. The angle between hr's hand and min's hand should be 10 deg.

Mohan le

3

in every 60 minutes hour hand moves 30 degrees. so at 14:20 ( it means that 20 minutes have past since last turn) hour hand moves 20*30/60 = 10 degrees so the answer is 10 degrees...

salimocho le

0

10 degrees

k naveen kumar le

1

At first I thought this was a dumb question but after seeing how many people here think the answer is zero, I've changed my mind. lol

JP le

1

The angle between hour and minute hand in 4:20 is 10 degrees. For a minute, the hour hand rotates by 30/60 = 1/2 degrees. hence, for 20 minutes it rotates by an angle of 20*1/2 = 10 degrees.

mounika le

0

The formula is 180 - | 180 - | m * 6 - (h * 30 + m * 0.5) |

Vikram le

0

Heres the complete formula.. for better understanding.. ABS is absolute value 180 - ABS (180 - ABS ( m * 6 - (h * 30 + m * 0.5) ) )

Vikram le

5

have you ppl looked at an analog clock recently it is 0 or 360 degrees

anonymous le

2

An analogue clock is degrees. 360/12=30 degrees per hour 360/60=6 degrees per minute So for 4 hours - 30*4=120 degrees For 20 mins - 20*6=120 degrees therefore, Answer is zero

Yulia le

3

20 minutes is 1/3 (20/60) of the way around the dial, 4 o'clock is also 1/3 of the way around a clock (4/12), so they are perfectly aligned and the angle between them must be zero.

Kent Lauridsen le

0

There are two approaches to this question: - If you assume the hour hand stays put and only moves every hour o'clock (which is a simplification, but a reasonable one), then the angle is 0º. - If you assume the hour hand rotates at a constant angular speed, then the answer is 10º. Since there's 360º / 12 = 30º between hours: + The minute hand points at 4. That's 30º x 4 = 120º. + The hour points slightly past 4. Since a third of the hour has passed (20' = 60' / 3), then the minute hour has moved a third of the way between hours. Hence the hand is at 120º + 30º / 3 = 130º. The difference between the two hands is 130º - 120º = 10º So I guess you get some poits for saying 0º, more points for saying 10º. My question is, did you get to use pen and paper, or you had to answer on the spot?

Juan Mejías le

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