Given a 14 digit date time value as input (D), whose format is YYYYMMDDHHMISS.
YYYY – represents year (Examples: 1947, 2000, 2015)
MM – represents month (Examples: 12, 01, 03)
DD – represents day (Examples: 31, 01, 15)
HH – represents hour (Examples: 00, 01, 12, 23)
MI – represents minute (Examples: 59, 50, 00, 05)
SS – represents second (Examples: 59, 50, 00 06)

You will also be given another integer, called the offset value (O), in seconds. You are required
to print a 14 digit output date in the format YYYYMMDDHHMISS which is adjusted for the offset from the input date.

Constraints:
10010101000000

Question

Given a 14 digit date time value as input (D), whose format is YYYYMMDDHHMISS.
YYYY – represents year (Examples: 1947, 2000, 2015)
MM – represents month (Examples: 12, 01, 03)
DD – represents day (Examples: 31, 01, 15)
HH – represents hour (Examples: 00, 01, 12, 23)
MI – represents minute (Examples: 59, 50, 00, 05)
SS – represents second (Examples: 59, 50, 00 06)

You will also be given another integer, called the offset value (O), in seconds. You are required
to print a 14 digit output date in the format YYYYMMDDHHMISS which is adjusted for the offset from the input date.

Constraints:
10010101000000 < D < 39991231235959
-94638758399 < O < 94638758399

Sample Input:
19470815000008
17

Sample Output:
19470815000025

Explanation:

The input 19470815000008 represents August 15, 1947 00:00:08. If you adjust the input date with 17 seconds, you will get the date August 15, 1947 00:0025. Hence the output is 19470815000025.

roy · Accepted Answer

long long a;
    scanf("%lld",&a);
    int b;
    scanf("%d",&b);
    printf("%lld",a+b);

Mallow Technologies

Question d’entretien chez Mallow Technologies

Réponse à la question d'entretien

Entreprises suivies

Recherche d’emplois