split an array into even and odd array in sorted order and main logic should contain only two loop

Question

Utilisateur anonyme · Accepted Answer

think about the question for several minutes and then answer

Answer -Ambar Singh · Answer

#include 

int main()
{
    
    int i,a[]={1,2,3,4,5,6,7,8,9};
     printf("Even		Odd

");
    for(i=0;i<9;i++){
        
        if(a[i]%2==0)
        printf("%d
",a[i]);
        
        else
        printf(" 		%d
",a[i]);
   
                }

    return 0;
}

Shweta Rastogi · Answer

// split an array into even and odd array in sorted order and main logic should contain only two loop 


import java.util.Scanner;




class ArrayInput
{
	  

	public static void main(String args[])
	{
		
		Scanner in=new Scanner(System.in);
                ArrayInput ob=new ArrayInput();

	//Print array
		System.out.println("Enter the size of array");
		int n=in.nextInt();
		int a[]= new int[n];
		System.out.println("Enter the elements of array");
		for(int i=0;ia[j])
				{
				
				int temp=a[i];
				a[i]=a[j];
				a[j]=temp;
				}
				//System.out.println(a[i]);
			}
		}
	

	//even-odd array
		System.out.println("Even elements of array are:");
                for(int i=0;i

Priti Jha · Answer

Get Data



function getDataArray(){
var even = [];
var odd = [];
var data = [3, 6, 2, 7];
for(var i=0; i

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