J'ai postulé en ligne. Le processus a pris 2 semaines. J'ai passé un entretien chez Wayfair (San Francisco, CA) en oct. 2022
Entretien
One hiring manager round followed by a technical (coding + system design short answers) and finally an on-site. Unfortunately, they didn't go through with the on-site because the role was filled
Questions d'entretien [1]
Question 1
We are working on a clone of Facebook that allows users to share content with their social network. Users view posts in an infinite stream. Our product only has a few thousand users but we expect it to be as popular as Facebook very soon! We want to add a live numeric count to every post showing how many friends the post's author has. Right now, our database has two tables, 'user' and 'user_relationship'. Each friendship relation appears in the database exactly once. The database definition includes: USER 'id' (primary key) 'name' 'created_date' USER_RELATIONSHIP 'id' (primary key, unique to each relationship) 'user1_id' (indexed) 'user2_id' (indexed) 'start_date' What would you do with the database in order to provide this feature for use at a large scale?
HR reached out and scheduled the discussion - discussed the details of the position.
One Online assignment
Scheduled one DSA round. - medium leetcode
System design round discussion - where we discussed the details of the different component of the system
Questions d'entretien [1]
Question 1
They always ask the same question from each of the candidates.
J'ai postulé en ligne. J'ai passé un entretien chez Wayfair (Toronto, ON) en août 2025
Entretien
Overall ok but the coding test environment is like a black box that you just can’t debug. If you solve by debugging, you’re doomed. LeetCode won’t really prepare you for this.
J'ai postulé en ligne. Le processus a pris 1 jour. J'ai passé un entretien chez Wayfair (Bengaluru) en avr. 2025
Entretien
The 1st round was Coding round on Hacker rank, the question was to validate if given set of IP address or not.
The second question was on Task scheduling which was based on hashmap.
